If it's not what You are looking for type in the equation solver your own equation and let us solve it.
6u^2-26u+20=0
a = 6; b = -26; c = +20;
Δ = b2-4ac
Δ = -262-4·6·20
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-14}{2*6}=\frac{12}{12} =1 $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+14}{2*6}=\frac{40}{12} =3+1/3 $
| 7m-12m-11=3(m-2) | | (-8,2)m=2 | | -3(x+7)=-6x-6 | | -2x+16=6(x-8) | | -12x+2(x-5)+7x=5x-50 | | 5x/2-2=4 | | -8(v+6)=3v-26 | | -12x+2(x-5)=7x=5x-50 | | (x/4)*6^1028=537 | | -8v=5v+15 | | -5x+8x-14=3(x-4)-34 | | X2-y2=12Y+24 | | -6t+12=-2(3t+6) | | z-3.8/0.2=-3 | | 2.4x1-1.08x2=0 | | -1/2(5k-20)=95 | | 4a-7=2a+9 | | 8x-8x=-4 | | 2+(9+m)=(2+9)+m=11+m | | x÷7=-2 | | 3/5+7/6x=1/8x | | (2x-4)(x)=240 | | -x-8=-2x+10 | | 49=12x-5x | | 2(x+5)=2(5+x) | | 3r+7=45r+14 | | 7(1x+140)=1x+5 | | (x)(2x)=729 | | 3p-8=13-46p | | 7x+14x=27 | | 6(x-1=2x+8 | | 3x+2=10-(4x-4) |